1 Find the surface area of the cylinder
we know that
the surface area of a cylinder is equal to
[tex] SA=2*area\ of\ the\ base +perimeter\ of\ the\ base*height [/tex]
[tex] area\ of\ the\ base= \pi* r^{2}[/tex]
[tex] perimeter\ of\ the\ base= 2*\pi* r [/tex]
[tex] height=r [/tex]
Substitute
[tex] SA=2*\pi*r^{2} +2*\pi*r*r [/tex]
[tex] SA=4*\pi *r^{2}[/tex]
2 Find the surface area of the cone
we know that
the surface area of a cone is equal to
[tex] SA=\pi*r^{2}+\pi *r*l [/tex]
[tex] SA=\pi *r^{2}+\pi *r*2*r [/tex]
[tex] SA=3* \pi *r^{2}[/tex]
3 Compare the surface area of the cylinder with the surface area of the cone
[tex] 4 \pi r^{2}\neq 3 \pi r^{2}[/tex]
therefore
the answer is
False
