Answer:
The resistance interval is [tex]R = 1.8 \pm 0.037[/tex]
Explanation:
From the question we are told that
The voltage is V = 9 V
The current is [tex]I = 5 \pm 0.1[/tex]
The maximum current would be
[tex]I_{max} = 5 + 0.1 = 5.1 \ A[/tex]
The minimum current would be
[tex]I_{min} = 5 - 0.1 = 4.9 \ A[/tex]
The maximum resistance is
[tex]R_max = \frac{V}{I_{min}}[/tex]
[tex]R_max = \frac{9}{4.9}[/tex]
[tex]R_max = 1.837 \Omega[/tex]
The minimum resistance is
[tex]R_{min} = \frac{V}{I_{max}}[/tex]
[tex]R_{min} = \frac{9}{5.1}[/tex]
[tex]R_{min} = 1.765 \Omega[/tex]
and [tex]R = \frac{9}{5} = 1.8 \Omega[/tex]
The interval R lies is
[tex]R = 1.8 \pm 0.037[/tex]
