Answer:
answer C
Step-by-step explanation:
hello
because this is not allowed to divide by 0 I would take x real different from 0 and from -5/4
[tex]\dfrac{8x^3-10x^2-25x}{4x^2+5x}=\dfrac{x(8x^2-10x-25)}{x(4x+5)}=\\\dfrac{8x^2-10x-25}{4x+5}=\dfrac{(4x+5)(2x-5)}{4x+5}=2x-5[/tex]
indeed if we develop
[tex](4x+5)(2x-5)=8x^2-20x+10x-25=8x^2-10x-25[/tex]
hope this helps
do not hesitate if you have any question
