Write an equation in point slope and slope intercept form of a line that passes through the given point and has the given slope m.(If possible please show work)

The point-slope formula is [tex]y-y_{1}=m(x-x_{1} )[/tex]. The slope-intercept formula is [tex]y=mx+b[/tex]. Since we are given the point and slope, we can directly plug it into the point-slope formula.

Point-Slope

[tex]y-(-4)=-\frac{1}{2}(x- (-3))[/tex]

[tex]y+4=-\frac{1}{2} (x+3)[/tex]

To find the slope-intercept form, we can manipulate the point-slope form to get the slope-intercept form.

Slope-Intercept

[tex]y+4=-\frac{1}{2}x-\frac{3}{2}[/tex]

[tex]y=-\frac{1}{2}x-\frac{11}{2}[/tex]

nermay7 nermay7 · Answer 2 · 2020-07-13T02:37:09+02:00

Answer: Point slope form y+4= -1/2(x+3)

Slope intercept form: y=-1/2x -11/2

Step-by-step explanation:

(-3,-4) : m= -1/2

So we know the slope and to write it in point slope form it will be like ,

y- b = m(x-a) Where b is the y value and a is the x value and m in this case is the slope .

y- (-4) = -1/2 ( x-(-3) which reduces to y+4= -1/2(x+3)

Now to write it in slope intercept form it will be like y=mx+b and we kow htat m is the slope but we do not know b the y-intercept. But using the given coordinates we could plot it into the formula and solve for b.

y = mx +b

We know that y is -4

We know that m is -1/2

we know that x is -3

so -4 = -1/2(-3) + B

-4 = 3/2 + b

-3/2 -3/2

b= -11/2

We know now that the y intercept is -11/2 so we could write it in slope intercept form.

y= -1/2x - 11/2