Answer:
14.4 m
The distance covered by the body is 14.4 m.
Solution,
Initial velocity(u)= 0 m/s( according to Question, the body starts from rest.that's why initial velocity(u) becomes zero.
Acceleration (a)= 0.2 m/s
Time (t):
[tex] \frac{1}{5} minute = \frac{1}{5 } \times 60 \: seconds[/tex]
[tex] = 12 \: seconds[/tex]
Now,
Applying third equations of motion:
[tex]s = ut + \frac{1}{2} a {t}^{2} \\ s = 0 \times 12 + \frac{1}{2} \times 0.2 \times {(12)}^{2} \\s = 0 + 14.4 \\ s = 14.4 \: metre[/tex]
Thus, the distance covered by the body is 14.4 metre.
Further more information:
Application of equation of motion in different situation:
- When a certain object comes in motion from rest, in the case, initial velocity(u)= 0 m/s
- When a moving object comes in rest,in the case, final velocity(v)= 0 m/s
- If the object is moving with uniform velocity, in the case, (u=v)
- If any object is thrown vertically upward, in the case, acceleration (a)= -g
- When an object is falling from certain height, in the case, u= 0 m/s
- When an object is thrown vertically upwards in the case, final velocity at maximum height becomes 0.
