Respuesta :

Answer:

A. 3

Step-by-step explanation:

[tex] log_{4}(64) = y \\ 64 = {4}^{y}(\because if \: log_a b = x \implies b = a^x) \\ {4}^{3} = {4}^{y} \\3 = y..(equal \: bases \: have \: equal \: exponents ) \\ \huge \purple { \boxed{y = 3}}[/tex]