The question is poorly formatted:
#include <stdio.h>
int main() {
int arr [5] = {1, 2, 3, 4, 5};
arr [1] = 0;
arr [3] = 0;
for (int i = 0;i < 5; i+=1)
printf("%d", arr[i]);
return 0;
}
Answer:
The output is 10305
Explanation:
I'll start my explanation from the third line
This line declares and initializes integer array arr of 5 integer values
int arr [5] = {1, 2, 3, 4, 5};
This line sets the value of arr[1] to 0
arr [1] = 0;
At this point, the content of the array becomes arr [5] = {1, 0, 3, 4, 5};
This line sets the value of arr[3] to 0
arr [3] = 0;
At this point, the content of the array becomes arr [5] = {1, 0, 3, 0, 5};
The next two lines is an iteration;
The first line of the iteration iterates the value of i order from 0 to 4
for (int i = 0;i < 5; i+=1)
This line prints all elements of array arr from arr[0] to arr[4]
printf("%d", arr[i]);
So, the output will be 10305
