Your question is poorly formatted
#include <stdio.h>
int main(void) {
int i, t[4];
t[3] = 0;
for (i = 1; i >= 0; i--)
t[i] = t[3] * i;
printf("%d", +t[1]);
return 0;
}
Answer:
It outputs 0
Explanation:
I'll start my explanation from the third line
This line declares an integer variable i and an array of 4 elements of type integer
int i, t[4];
This line initialize the 3rd index element to 0
t[3] = 0;
The next two lines is an iteration;
The first line of the iteration iterates the value of i in descending order from 1 to 0
for (i = 1; i >= 0; i--)
This line of the iteration calculates t[1] as t[3] * i and t[0] as t[3] * i; Since t[3] is 0; both t[1] and t[0] will be 0
t[i] = t[3] * i;
This line prints t[1] which is 0
printf("%d", +t[1]);
