Need help finding the missing length to the attached triangle.

Answer:
1500
Step-by-step explanation:
Let the length of the perpendicular dropped from the right angle to the hypotenuse be h units.
Now by geometric mean property:
[tex]h = \sqrt{1600 \times 900} \\ h = 40 \times 30 \\ h = 1200 \: units \\ Next \: by \: Pythagoras \: Theorem: \\ {x}^{2} = {h}^{2} + {900}^{2} \\ {x}^{2} = {1200}^{2} + {900}^{2} \\ {x}^{2} = 1440000 + 810000 \\ {x}^{2} = 2,250,000 \\ x = \sqrt{2,250,000} \\ \huge \red{ \boxed{x = 1500\: units }}[/tex]
Answer:
1500
Step-by-step explanation:
Use the right triangle altitude theorem.
x/900 = 2500/x
x^2 = 900 * 2500
x = sqrt(900 * 2500)
x = 30 * 50
x = 1500