**BRAINLIEST IF ANSWERED***

A regular hexagon is shown. What is the measure of half the side length, b, rounded to the nearest whole inch? Use the appropriate trigonometric ratio to solve. *
6 in

24 in

14 in

7 in

BRAINLIEST IF ANSWERED A regular hexagon is shown What is the measure of half the side length b rounded to the nearest whole inch Use the appropriate trigonomet class=

Respuesta :

Answer:

(D)7 in.

Step-by-step explanation:

A regular hexagon can be divided into six equilateral triangles.

Therefore:

[tex]b=\dfrac{c}{2}[/tex]

Applying Pythagoras Theorem

[tex]c^2=12^2+b^2\\c^2=12^2+(\frac{c}{2})^2\\c^2-(\frac{c}{2})^2=12^2\\c^2-\dfrac{c^2}{4}=144\\\dfrac{4c^2-c^2}{4}=144\\\dfrac{3c^2}{4}=144\\$Cross multiply\\3c^2=144 \times 4\\3c^2=576\\$Divide both sides by 3\\c^2=192\\$Therefore:\\c=\sqrt{192}\\c=8\sqrt{3}$ in.[/tex]

Recall that b=c/2

Therefore:

[tex]b=4\sqrt{3} \approx 7$ in.[/tex]

The value of b is 7 inches.