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For three consecutive numbers, the sum of the first number, twice the second and 7 less than the third is 133. What are the three numbers?

Respuesta :

mlarsen5000

Answer:

34, 35, 36

Step-by-step explanation:

1st number = x

2nd number = x+1

3rd number = x+2

So the equation would be:

x+2(x+1)+(x+2)-7=133

x+2x+2+x+2-7=133

4x-3=133

4x=136

x=34

      Three consecutive numbers justifying the condition given in the statement will be 34, 35, 36.

Algebraic expression from a verbal statement:

  •   Define the variables to form an algebraic expression from a verbal statement first.
  •   Then form the expression or equation as per given verbal statement.

Let three consecutive number are,

n, (n + 1), (n + 2)

First statement given,

" The sum of first number, twice the second number"

Expression for the statement → [n + 2(n + 1)]

Second statement → " 7 less than the third number"

Expression for the statement → (n + 2) - 7

Combine the expressions,

"The sum of first number, twice the second number and 7 less than the third number is 133"

Form the equation and simplify,

n + 2(n + 1) + (n + 2) - 7 = 133

n + 2n + 2 + n + 2 - 7 = 133

(n + 2n + n) + (2 + 2 - 7) = 133

4n - 3 = 144

4n = 136

n = 34

         Therefore, the numbers are,

                            1st number → n = 34

                            2nd number → (n + 1) = 35

                            3rd number → (n + 2) = 36

Learn more about the solution of equations here,

https://brainly.com/question/864749?referrer=searchResults

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