Please can someone help?

Hey there! :)
Answer:
(5, -2), or x = 5 and y = -2.
Step-by-step explanation:
We can solve the two equations algebraically by eliminating a variable:
2x + 5y = 0
3x - 4y = 23
Eliminate the x variable by finding the least common multiple and multiplying both equations:
3(2x + 5y = 0)
2(3x - 4y = 23)
Distribute and subtract the bottom equation from the top:
6x + 15y = 0
6x - 8y = 46
------------------
0x + 23y = -46
23y = -46
y = -2.
Plug in y into an equation to solve for x:
2x + 5(-2) = 0
2x - 10 = 0
2x = 10
x = 5. Therefore:
The solution to this equation is (5, -2), or x = 5 and y = -2.
Answer:
x = 5; y = -2
Step-by-step explanation:
2x + 5y = 0
3x - 4y = 23
Let's eliminate y. Multiply the first equation by 4. Multiply the second equation by 5. Then add them.
8x + 20y = 0
(+) 15x - 20y = 115
------------------------------
23x = 115
x = 5
Now we substitute 5 for x in the first equation and solve for y.
2(5) + 5y = 0
5y = -10
y = -2
Solution: x = 5; y = -2