Answer:
0.901 M
Explanation:
The concentration of the CO(g) in the equilibrated mixture is shown below:
[tex]K_C = \frac{H_2\times CO_2}{CO\times H_2O}[/tex]
where,
[tex]K_C[/tex] = equilibrium constant
And, we placing these above values to the formula shown as above
So, the concentration of CO(g) is
[tex]= \frac{3.33 \times 0.134}{0.66\times 0.750}[/tex]
= [tex]\frac{0.44622}{0.495}[/tex]
= 0.901 M
We simply applied the above formula in order to determine it and so that the correct answer could arrive