contestada

A 45-mH inductor is connected to an ac source of emf with a frequency of 250 Hz and a maximum emf of 20 V. If the voltage across the inductor is +20 V at time t = 0, what is the voltage at time t = 2.0 ms? Assume the phase constant is zero.

Respuesta :

Answer:

-20v

Explanation:

Data provided in the question as per the given situation

L = 45 mH

f = 250 Hz

V_o = 20V

Based on the above information, let us assume voltage across inductor be V at t

So,

[tex]V = 20 sin (2 \pi \times 250\times t + \frac{\pi}{2})[/tex]

t = 2 ms

Now

The voltage at time t = 2.0 ms is

[tex]V_1 = 20 sin (500\times 2\times 10^{-1} \times \pi + \frac{\pi}{2})[/tex]

[tex]= 20 sin(\pi + \frac{\pi}{2} )[/tex]

= -20 volt

= -20v

We simply solved the above equation so that the correct voltage could come

Lanuel

The the voltage at time (t) = 2.0 ms is equal to -20 Volts.

Given the following data:

  • Inductance = 45-mH to H = 0.045 Henry
  • Frequency = 250 Hz
  • Max. emf = 20 V
  • Time = 2.0 ms to s = 0.2 seconds

To determine the the voltage at time (t) = 2.0 ms:

In an AC source, the voltage across the inductor is given by the formula:

[tex]V = Esin(2\pi ft + \frac{\pi}{2} )[/tex]

When time (t) = 2.0 ms:

[tex]V = 20sin(2\pi \times 250 \times 0.002+ \frac{\pi}{2} )\\\\V = 20sin(\pi + \frac{\pi}{2} )\\\\V = 20sin(270)\\\\V=20 \times -1[/tex]

Voltage = -20 Volts.

Read more: https://brainly.com/question/15121836

Otras preguntas