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Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options. The radius of the circle is 3 units. The center of the circle lies on the x-axis. The center of the circle lies on the y-axis. The standard form of the equation is (x – 1)² + y² = 3. The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

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abidemiokin
  • The center of the circle lies on the x-axis
  • The radius of the circle is 3 units.
  • The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

The standard equation of a circle is expressed as:

[tex]x^2+y^2+2gx+2fy+C=0[/tex]

  • Centre is (-g, -f)
  • radius = √g²+f²-C

Given a circle whose equation is [tex]x^2 + y^2 - 2x - 8 = 0.[/tex]

Get the centre of the circle

2gx = -2x

2g = -2

g = -1

Similarly, 2fy = 0

f = 0

Centre = (-(-1), 0) = (1, 0)

This shows that the center of the circle lies on the x-axis

r = radius = √g²+f²-C

radius = √1²+0²-(-8)

radius =√9 = 3 units

The radius of the circle is 3 units.

For the circle x² + y² = 9, the radius is expressed as:

r² = 9

r = 3 units

Hence the radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

Learn more on circles here: https://brainly.com/question/23226948

xaviercreed1

Answer:

a, b and e

Step-by-step explanation:

i got it correct on edge

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