Answer:
0.1997 or 19.97%
Step-by-step explanation:
Have taken course online (H) = 23%
Have NOT taken course online (N) = 77%
Have taken course online and don't believe they provide same value (H&D) = 61%
Have NOT taken course online and don't believe they provide same value (N&D) = 73%
The probability that a student has taken a course online given that she does not believe that online courses provide the same educational value as one taken in person is;
[tex]P(H|D)=\frac{P(H)*P(H\&D)}{P(H)*P(H\&D)+P(N)*P(N\&D)}\\P(H|D)=\frac{0.23*0.61}{0.23*0.61+0.77*0.73}\\P(H|D)=0.1997[/tex]
There is a 0.1997 or 19.97% chance that she has taken an online course before.