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Answer:
The volume of the added acid at the equivalence point in case when titration is done with KOH is,
VHI * MHI = VKOH * MKOH
VHI = 20.ml * 0.200 M / 0.100 M
VHI = 40.0 ml
The volume of the added acid at the equivalence point in case when titration is done with CH3NH2 is,
VHI * MHI = VCH3NH2 * MCH3NH2
VHI = 20.0 ml * 0.200 M / 0.100 M = 40.0 ml
As HI is the strong acid and KOH is the strong base, therefore, the pH will be neutral at the equivalence point.
On the other hand, as HI is the strong acid and CH3NH2 is the weak base, therefore, pH will be acidic at the equivalence point.
When The volume of the added acid at the equivalence issue in the matter when titration is done with KOH is, VHI = 40.0 ml
What is the Equivalence point?
When The volume of the added acid at the equivalence issue in the matter when titration is done with KOH
Then VHI * MHI = VKOH * MKOH
After that VHI = 20.ml * 0.200 M / 0.100 M
Now, VHI = 40.0 ml
Then The volume of the added acid at the correspondence point in the matter when titration is done with CH3NH2 is,
Then VHI * MHI is = VCH3NH2 * MCH3NH2
After that, VHI is = 20.0 ml * 0.200 M / 0.100 M = 40.0 ml
As HI is the strong acid and KOH is the strong ground, Thus, the pH will be neutral at the equivalence point.
On the different indicators, as HI is the strong acid and CH3NH2 is the weak base, Thus, pH will be acidic at the equivalence point.
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