Answer:
The difference in the water potential ∆P is 7 bar.
∆P = 7 bar
Step-by-step explanation:
Given;
The water potential in one plant cell was calculated to be -4 bar
P1 = -4 bar
The water potential in another cell was found to be -11 bar.
P2 = -11 bar
The difference in the water potential ∆P is;
∆P = P1 - P2
Substituting the given values;
∆P = -4 - (-11) bar
∆P = -4 +11 bar
∆P = 7 bar
