contestada

Joan conducted a study to see how common binge drinking is on her college campus. She defined "frequent binge drinking" as having five or more drinks in a row three or more times in the past two weeks. Out of 593 students who replied to her survey, 64 fit this criterion. Joan wants to construct a significance test for her data. She finds that the proportion of binge drinkers nationally is 13.1%. The z statistic for this data is __________.

Respuesta :

Answer:

z = -1.66

Step-by-step explanation:

Z-statistic:

[tex]z = \frac{X - p}{s}[/tex]

In which X is the found proportion.

p is the mean proportion.

[tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex] is the standard error for the data.

Out of 593 students who replied to her survey, 64 fit this criterion.

This means that [tex]X = \frac{64}{593} = 0.108[/tex]

She finds that the proportion of binge drinkers nationally is 13.1%.

This means that [tex]p = 0.131[/tex]

Also

[tex]s = \sqrt{\frac{0.131*0.869}{593}} = 0.014[/tex]

The z statistic for this data is

[tex]z = \frac{X - p}{s}[/tex]

[tex]z = \frac{0.108 - 0.131}{0.014}[/tex]

[tex]z = -1.66[/tex]

Otras preguntas