Answer:
The constant factor remains a multiplier.
Step-by-step explanation:
The derivative of "a·f(x)" is a·f'(x). That is, the constant multiplier remains a constant multiplier, unchanged.
For ax^-1, the derivative is a(-x^-2) per the power rule. For your value of a=-5/2, this is ...
[tex]\dfrac{d}{dx}\left(-\dfrac{5}{2x}\right)=\left(-\dfrac{5}{2}\right)\left(\dfrac{-1}{x^2}\right)=\dfrac{5}{2x^2}[/tex]
