Answer:
The test statistic would be given by:
[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)
And replacing we got:
[tex]t=\frac{23.2-25}{\frac{8.6}{\sqrt{28}}}=-1.11[/tex]
Step-by-step explanation:
Information given
[tex]\bar X=23.6[/tex] represent the sample mean
[tex]s=8.6[/tex] represent the sample standard deviation
[tex]n=28[/tex] sample size
[tex]\mu_o =25[/tex] represent the value that we want to test
t would represent the statistic
System of hypothesis
We want to test if the true mean is lower than 25, the system of hypothesis would be:
Null hypothesis:[tex]\mu \geq 25[/tex]
Alternative hypothesis:[tex]\mu < 25[/tex]
The test statistic would be given by:
[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)
And replacing we got:
[tex]t=\frac{23.2-25}{\frac{8.6}{\sqrt{28}}}=-1.11[/tex]
