What is the distance from the origin to point P graphed on the complex plane below? On a coordinate plane, point P is at (2, negative 5). StartRoot 7 EndRoot StartRoot 29 EndRoot 7 29

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Answer:

√29

Step-by-step explanation:

Use the distance formula √((x2-x1)^2+(y2-y1)^2)

Since the first point is on the origin, (x1, y1) is (0, 0)

The second point is (2, -5)

Plug both points into the distance formula to get √29

The distance from origin to the point P is √29 units

How to determine the distance?

The given parameters are:

Origin = (0,0)

Point P = (2, -5)

The distance between these points is calculated as:

d =  √((x2-x1)^2+(y2-y1)^2)

So, we have:

d = √((2-0)^2+(-5 -0)^2)

Evaluate

d = √29

Hence, the distance from origin to the point P is √29 units

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