Sierra is selling bracelets to raise money for the Language Club at school. Each bracelet with yellow beads sells for $5. Each bracelet with orange beads sells for $6. She raised $660 for the club. The number of bracelets with yellow beads that Sierra sold is 8 more than twice the number of bracelets with orange beads. Let y represent the number of bracelets with yellow beads and r represent the number of bracelets with orange beads.Which system of equations will solve for the number of each type of bracelet sold? 5 y + 6 r = 660. y = 2 r + 8. 6 y + 5 r = 660. y = 2 r + 8. 5 y + 6 r = 660. y = r + 8. 6 y + 5 r = 660. r = 2 y + 8.

Total money raised by bracelets with yellow beads = Number of bracelets sold [tex]\times[/tex] Money raised by sale of one such bracelet = [tex]5y[/tex]

Also Given that Number of bracelets with Orange beads is represented by [tex]r[/tex]

Each bracelet with orange beads is sold for $6.

Total money raised by bracelets with orange beads = Number of bracelets sold [tex]\times[/tex] Money raised by sale of one such bracelet = [tex]6r[/tex]

Given that total money raised by sale of both type of bracelets is $660.

so, the first equation becomes:

[tex]5y+6r=660 ....... (1)[/tex]

It is also given that "The number of bracelets with yellow beads that Sierra sold is 8 more than twice the number of bracelets with orange beads"

[tex]\Rightarrow r =2r+8 ...... (2)[/tex]

So, by equation (1) and (2), the system of equations is:

[tex]5y+6r=660\\y=2r+8[/tex]

Dixson500 Dixson500 · Answer 2 · 2020-12-01T19:16:49+01:00

Dixson500 Dixson500

01-12-2020

Answer:

It's A.

Step-by-step explanation:

I just got it right on my unit test review.

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