Answer:
We have the equation
[tex]\frac{4*a^2*b^2*c}{-3*a*b} + \frac{8c^2}{15}[/tex]
First, we want the same denominator in both equations, so we can multiply in the left by 5, and in the right bt -ab, and now we have:
[tex]\frac{20*a^2*b^2*c}{-15*a*b} + \frac{-ab8c^2}{-15ab} = \frac{-20*a^2*b^2*c +8*a*b*c^2}{15*a*b}[/tex]
Now we have all in the same rational.
The only restriction in this type of equation is that the denominator never can be zero.
so 15*a*b = 0 is a restriction:
This means that a can not be zero, and b can not be zero.
