Answer:
The answer is
Step-by-step explanation:
[tex] {64}^{ \frac{2}{3} } \times {64}^{ \frac{1}{ 3} } [/tex]
Since they have the same base and are multiplying we add the exponents using the rules of indices
So we have
[tex] {64}^{ \frac{2}{3} + \frac{1}{3} } [/tex]
Which is
[tex] {64}^{ \frac{3}{3} } [/tex]
And 3/3 = 1
[tex] {64}^{1} [/tex]
We have the final answer as
Hope this helps you