Answer:
The inductive reactance is 0.8281 Ω/mile
Explanation:
Given;
frequency, f = 60 Hz
space between the center, GMD = 20 ft
The inductive reactance per mile is calculated as;
[tex]X_L =X_a + X_d\\\\X_L = 2.022*10^{-3} *f *ln\frac{1}{GMR} + 2.022*10^{-3} *f *ln\ GMD[/tex]
Where;
GMR is geometric mean radius (obtained from manufacturer's table)
GMD is geometric mean distance
For Partridge conductor, GMR = 0.0217 ft;
Xa = 2.022 x 10⁻³ x 60 x ln (1 / 0.0217)
Xa = 0.4647 Ω/mile
[tex]X_d[/tex] = 2.022 x 10⁻³ x f x ln GMD
[tex]X_d[/tex] = 2.022 x 10⁻³ x 60 x ln(20)
[tex]X_d[/tex] = 0.3634 Ω/mile
Inductive reactance;
[tex]X_L = X_a + X_d\\\\X_L = 0.4647 \ ohms/mile \ + 0.3634 \ ohms/mile\\\\X_L = 0.8281 \ ohms/mile[/tex]
Therefore, the inductive reactance is 0.8281 Ω/mile
