Write the standard equation of the circle in the graph.

A. (x + 3)squared + (y - 2)squared = 9
B. (x - 3)squared + (y + 2)squared = 9
C. (x - 3)squared + (y + 2)squared = 18
D. (x + 3)squared + (y - 2)squared = 18

Write the standard equation of the circle in the graph A x 3squared y 2squared 9 B x 3squared y 2squared 9 C x 3squared y 2squared 18 D x 3squared y 2squared 18 class=

Respuesta :

The centre is (a,b) = (3,-2)
The radius is r = 3

The equation of a circle is (x-a)² + (y-b)² = r²

Therefore, the equation of this circle is:
(x-3)²+(y+2)²=9      (B)

Answer: B. [tex](x-3)^2+(y+2)^2=9[/tex]

Step-by-step explanation:

From the given graph, it can be seen that the center of circle lies at (3,-2).

Radius = distance from the center to the boundary of circle.

=|3-0|=3 units

Standard equation of circle :

[tex](x-h)^2+(y-k)^2=r^2[/tex], where (h,k) is center and r is the radius of the circle.

Then , standard equation of the circle in the graph (having center (3,-2) and radius = 3 units)

[tex](x-3)^2+(y-(-2))^2=(3)^2[/tex]

[tex](x-3)^2+(y+2)^2=9[/tex]

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