Hello,
We may exchange x and y.
[tex]-A_1= \int\limits^b_0 {x^2-1} \, dx = \dfrac{b^3}{3} -b\\
-A_2= \int\limits^1_b {x^2-1} \, dx =- \dfrac{2}{3} - \dfrac{b^3}{3}+b\\
-A_1=-A_2==\textgreater\ b^3-3b+1=0\\
sol={1.532088886238 , -1.879385241572 , 0.347296355334 }\\
The\ solution\ is\ 0.347296355334 .[/tex]≈0.347
