Respuesta :

dasetka
11 - [tex] \frac{1}{2} [/tex]y = 3 + 6x   Subtract 11 from both sides
-[tex] \frac{1}{2} [/tex]y = 3 + 6x - 11   Combine like terms (3 and -11)
-[tex] \frac{1}{2} [/tex]y = 6x - 8   Multiply both sides by -2 to cancel out the fraction
y = -12x  + 16

Answer:

[tex]y=-12x+16[/tex]

Step-by-step explanation:

We have been given an equation [tex]11-\frac{1}{2}y=3+6x[/tex]. We are asked to solve our given equation for y.

Subtract 11 from both sides:

[tex]11-11-\frac{1}{2}y=3-11+6x[/tex]

[tex]-\frac{1}{2}y=-8+6x[/tex]

Multiply both sides by -2:

[tex](-2)-\frac{1}{2}y=-2(-8+6x)[/tex]

[tex]y=(-2)(-8)+(-2)(6x)[/tex]

[tex]y=16-12x[/tex]

[tex]y=-12x+16[/tex]

Therefore, our required equation would be [tex]y=-12x+16[/tex].

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