Respuesta :

caylus
Hello,

[tex] u_{4}= 12+(4-4)*\frac{1}{4}\\ u_{3}= 12+(3-4)*\frac{1}{4} \\ u_{2}= 12+(2-4)*\frac{1}{4} \\ u_{1}= 12+ (1-4)*\frac{1}{4} \\ u_{5}= 12+ (5-4)*\frac{1}{4} \\ u_{6}= 12+ (6-4)*\frac{1}{4} \\ ...\\ \boxed{u_{n}= 12+ (n-4)*\frac{1}{4}} \\ [/tex]