Answer:
Mr. Rodriguez saves and invests $65,000.
Step-by-step explanation:
Let Mr. Rodriguez has total money = $x
Now his investment in land = [tex]\frac{x}{2}[/tex]
Investment in stocks =[tex]\frac{x}{10}[/tex]
Investment in bonds =[tex]\frac{x}{20}[/tex]
So total investment =[tex]\frac{x}{2}[/tex]+[tex]\frac{x}{10}[/tex]+[tex]\frac{x}{20}[/tex]
= [tex]\frac{10x+2x+x}{20}[/tex]
= [tex]\frac{13x}{20}[/tex]
Remaining amount after investment is $35,000
So 35,000 = x - [tex]\frac{13x}{20}[/tex]
35,000 = [tex]\frac{20x-13x}{20}[/tex]
7x = 20 × 35,000
7x = 700,000
x = [tex]\frac{700,000}{7}[/tex]
x = $100,000
and investments = [tex]\frac{13x}{20}[/tex] = [tex]\frac{13\times100,000}{20}[/tex] = $65,000
Total amount of money that Mr. Rodriguez saves $65,000.
