Lines CD and DE are tangent to circle A shown below: If Arc CE is 112°, what is the measure of ∠CDE? a 124° b 136° c 68° d 56°

Answer:
C
Step-by-step explanation:
The central angle of this is 112 degrees. That is CAE is 112 degrees. That being the case, CDE is 90 + 90 + 112 = 292 Tangents make a 90 degree angle with the center of the circle.
CDE = 360 - 292 = 68
C
The measure of ∠CDE is 68degrees
This question bothers on circle geometry;
From the diagram, we can see that ACDE will form a quadrilateral. Since the sum of angles of a quadrilateral is 360degrees, hence;
[tex]<CDE + arcCE+<C+<E=360[/tex]
From the diagram, since CD and DE are both tangential to the circle at point C and E, this shows that <E = <E = 90°
substituting the given values in the formula;
[tex]<CDE+112+90+90=360\\<CDE + 292=360\\<CDE=360-292\\<CDE =68^0[/tex]
Hence the measure of ∠CDE is 68 degrees
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