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The following equation is often referred to as Euler's Formula; e^pii+1=0 Use what you know about complex numbers to show that this equation is true. In other words, show that e^pii+1=0 __ If someone could please help me understand the proof and the answer to this ill give you brainliest!! thank you

Respuesta :

Alfpfeu

Answer:

[tex]\large \boxed{e^{i\pi}+1=0}[/tex]

Step-by-step explanation:

Hello, please consider the following.

For any x real number,

[tex]e^{ix}=cos(x)+i\cdot sin(x)\text{, right? So}\\\\e^{i\pi}=cos(\pi)+i\cdot sin(\pi)\\\\e^{i\pi}=-1+i\cdot 0=-1\\\\\text{ We add 1 to both sides of the equation.}\\\\\large \boxed{e^{i\pi}+1=0}\\[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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