An architect maps two buildings, which are located on a piece of land, onto a coordinate plane. He wants to build a wall at the diagonal AC to divide the piece of land into two parts. What will be the length of the wall? A. 65–√ units B. 6 units C. 237−−√ units D. 2 units

An architect maps two buildings which are located on a piece of land onto a coordinate plane He wants to build a wall at the diagonal AC to divide the piece of class=

Respuesta :

Answer:

[tex] 6\sqrt{5} units [/tex]

Step-by-step Explanation:

The length of the wall = diagonal AC = distance between point A (-6, -2) and point C (6, 4).

Distance formula between two points on a graph (d) = [tex] \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Where,

[tex] A(-6, -2) = (x_1, y_1) [/tex]

[tex] C(6, 4) = (x_2, y_2) [/tex]

[tex] d = \sqrt{(6 - (-6))^2 + (4 -(-2))^2} [/tex]

[tex] d = \sqrt{(6 + 6)^2 + (4 + 2)^2} [/tex]

[tex] d = \sqrt{(12)^2 + (6)^2} [/tex]

[tex] d = \sqrt{144 + 36} [/tex]

[tex] d = \sqrt{180} [/tex]

[tex] d = \sqrt{36*5} [/tex]

[tex] d = 6\sqrt{5} [/tex]

The length of the wall = [tex] 6\sqrt{5} units [/tex]