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Where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the acceleration (in m/s²) and s is the distance (in meters). Find v when u is 8 m/s, a is 3 m/s², and s is 19 meters. A. 15 m B. 130−−−√ m C. 178−−−√ m D. 13 m

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Answer:

C. 178−−−√ m

Step-by-step explanation:

Given the following :

v = final velocity (in m/s)

u = initial velocity (in m/s)

a = acceleration (in m/s²)

s = distance (in meters).

Find v when u is 8 m/s, a is 3 m/s², and s is 19 meters

Using the 3rd equation of motion :

v^2 = u^2 + 2as

v^2 = 8^2 + 2(3)(19)

v^2 = 64 + 114

v^2 = 178

Take the square root of both sides :

√v^2 = √178

v = √178