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What is the slope of the line? x + 3 y = 10 x+3y=10x, plus, 3, y, equals, 10 Choose 1 answer: Choose 1 answer: (Choice A) A 1 3 3 1 ​ start fraction, 1, divided by, 3, end fraction (Choice B) B 1 10 10 1 ​ start fraction, 1, divided by, 10, end fraction (Choice C) C − 1 10 − 10 1 ​ minus, start fraction, 1, divided by, 10, end fraction (Choice D) D − 1 3 − 3 1 ​

Respuesta :

abidemiokin

Answer:

-1/3

Step-by-step explanation:

The standard from of equation of a line written in slope-intercept format is expressed as y = mx+c where c is the slope of the line and c is the y-intercept.

Given the equation of the line x+3y = 10, to get the slope of the line, we need write he equation in standard from first by making y the subject of the formula as shown;

[tex]x+3y = 10\\\\subtract\ x \ from \ both \ sides\\\\x+3y-x = 10 -x\\\\3y = -x+10\\\\Divide \ through\ by \ 3\\\\\frac{3y}{3} = -\frac{x}{3} +\frac{10}{3} \\\\[/tex]

[tex]y = -\frac{1}{3}(x) +\frac{10}{3} \\[/tex]

Comparing the resulting equation with y = mx+c, the slope 'm' of the equation is -1/3

ninjathan300

Answer:

The answer is -1/3

Step-by-step explanation:

I got this answer on Khan Academy.

Hope this helps! :)

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