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BRAINLIEST, 5 STARS, 50 POINTS AND THANKS IF ANSWERED CORRECTLY.

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1. What are the solutions for x when y is equal to 0 in the following quadratic function?
y = x^2 + 4

2. What are the solutions for x when y is equal to 0 in the following quadratic function?
y = x^2 - 81

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Thank you if you answered!

Respuesta :

Answer:

see explanation

Step-by-step explanation:

(1)

x² + 4 = 0 ( subtract 4 from both sides )

x² = - 4 ( take the square root of both sides )

x = ± [tex]\sqrt{-4}[/tex] = ± 2i ← complex solutions

(2)

x² - 81 = 0 ( add 81 to both sides )

x² = 81 ( take the square root of both sides )

x = ± [tex]\sqrt{81}[/tex] = ± 9 ← real solutions

flikitrix

Answer:

1. -2

2. 9

Step-by-step explanation:

1. 0 = x2 + 4

  -4 = x2

  [tex]\sqrt{-4}[/tex] = x

x = -2

2. 0 = x2 - 81

   81 = x2

    [tex]\sqrt{81}[/tex] = x

 x = 9

    MARK IT BRAINLIEST!!!

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