Answer:
C) Distance =5 units
Step-by-step explanation:
[tex]x_1=1\\y_1=1\\x_2 =5\\y_2 = 4\\\\d = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^2 } \\\\d = \sqrt{(5-1)^2+(4-1)^2} \\\\d = \sqrt{(4)^2+(3)^2}\\ \\d = \sqrt{16+9}\\ d = \sqrt{25}\\ \\d = 5[/tex]
Using the formula for the distance between two points, it is found that the distance between points A and B is given by:
C) 5 units.
Suppose that we have two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The distance between them is given by:
[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
In this problem, the points are A(1,1) and B(5,4), hence:
[tex]D = \sqrt{(5-1)^2+(4-1)^2} = \sqrt{25} = 5[/tex]
Hence option C is correct.
More can be learned about the distance between two points at https://brainly.com/question/18345417
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