Respuesta :
Answer:
The tension in the cable is approximately 1440.0 N
Explanation:
The length of the beam = 8 m
The weight of the beam = 200 N
The angle made by the beam support cable = 53°
The weight of the person = 600 N
The position where the person stands = 2 m
The forces acting are the weight of the cable acting at the center of the beam and the weight of the person acting at 2 m from the wall
Therefore, we have;
Sum of moments = 0, which gives;
2000 × 4 + 2 × 600 - 8 × [tex]T_y[/tex] = 0
2000 × 4 + 2 × 600 = 8 × [tex]T_y[/tex]
[tex]T_y[/tex] = 9200/8 = 1150 N
The tension in the cable, T = The component of the force in the cable
The vertical component of the tension [tex]T_y[/tex] = T×sin(53)
Therefore;
T = [tex]T_y[/tex]/(sin(53)) = 1150/(sin(53 degrees)) = 1439.96 ≈ 1440 N
The tension in the cable, T is approximately 1440 N.
