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Suppose that it rains in Spain an average of once every 9 days, and when it does, hurricanes have a 2% chance of happening in Hartford. When it does not rain in Spain, hurricanes have a 1% chance of happening in Hartford. What is the probability that it rains in Spain when hurricanes happen in Hartford? (Round your answer to four decimal places.)

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Answer:

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Step-by-step explanation:

P[rains in spain] = 1/9

P[hurricane in hartford & rain in spain] = 0.03*1/9 = A

P[hurricane in hartford & no rain in spain] = 0.02*8/9

P[hurricane in hartford] = 0.03*1/9 + 0.02*8/9 = 0.19/9 = B

P[rain in spain | hurricane in hartford] = A/B = 3/19 <---------

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