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What is the concentration of A after 50.7 minutes for the second order reaction A → Products when the initial concentration of A is 0.250 M? (k = 0.117 M⁻¹min⁻¹)

Respuesta :

dsdrajlin

Answer:

0.101 M

Explanation:

Step 1: Given data

  • Initial concentration of A ([A]₀): 0.250 M
  • Final concentration of A ([A]): ?
  • Time (t): 50.7 min
  • Rate constant (k): 0.117 M⁻¹.min⁻¹

Step 2: Calculate [A]

For a second-order reaction, we can calculate [A] using the following expression.

1/[A] = 1/[A]₀ + k × t

1/[A] = 1/0.250 M + 0.117 M⁻¹.min⁻¹ × 50.7 min

[A] = 0.101 M

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