Answer:
The watered area is approximately 3783 square feet.
Step-by-step explanation:
The area that is watered due to the rotation of the spankler is a circular section area ([tex]A[/tex]), whose formula is:
[tex]A = \frac{\theta }{2}\times \frac{1}{360^{\circ}}\times 2\pi \times d^{2}[/tex]
Where:
[tex]d[/tex] - Water distance, measured in feet.
[tex]\theta[/tex] - Rotation angle, measured in sexagesimal degrees.
Given that [tex]d = 85\,ft[/tex] and [tex]\theta = 60^{\circ}[/tex], the watered area is:
[tex]A = \frac{60^{\circ}}{2} \times \frac{1}{360^{\circ}}\times 2\pi \times (85\,ft)^{2}[/tex]
[tex]A \approx 3783\,ft^{2}[/tex]
The watered area is approximately 3783 square feet.
