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Given that ΔABC is a right triangle with a right angle at C, if tan A = [tex]\frac{5}{4}[/tex], find the value for tan B.

A. tanB = [tex]\frac{3}{4}[/tex]
B. tanB = [tex]-\frac{4}{5}[/tex]
C. tanB = [tex]\frac{4}{5}[/tex]
D. tanB = [tex]-\frac{5}{4}[/tex]

Respuesta :

Answer:

C

Step-by-step explanation:

tan A = [tex]\frac{5}{4}[/tex] = [tex]\frac{opposite}{adjacent}[/tex] , thus

The opposite side is the adjacent side for B and the adjacent side is the opposite side for B, thus

tan B = [tex]\frac{4}{5}[/tex]

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