Answer: d - 2 and d cannot equal 8
Step-by-step explanation: To simplify this rational expression, start by factoring both the numerator and the denominator.
So factoring the numerator in this problem, we have a
trinomial that factors as the product of two binomials.
So we are looking for factors of +16 that add to -10 which are -8 and -2.
So we have (d - 8)(d - 2) in the numerator.
The denominator doesn't factor however.
So we have [tex]\frac{(d - 8)(d - 2)}{(d - 8)}[/tex] and the d - 8's cancel leaving us with d - 2.
The values d cannot be happen when the denominator is set equal to 0.
So we have d - 8 = 0 which means d = 8.
This means d = 8 wouldn't work!
