The final answer is -3,-1,1 and 4
What is the relation between roots and the biquadratic equation?
The biquadratic equation is of the form ax⁴+bx³+cx²+dx+e and hence
The sum of roots is -b/a, the sum of the product of two roots is c/a, the sum of the product of three roots is -d/a, and the product of all four roots is e/a.
Solving the given problem
There is no specific method of solving a biquadratic equation, hence we use the trial and error method and also some form of the root.
So finding f(1) = 1-1-13+1+12 = 0 hence 1 is a root.
finding f(-1) = 1-(-1)-13-1+12 = 0 hence -1 is also a root.
So let other roots be p,q
Now we can use sum of roots formula which is p+q+1-1= 1, hence p+q=1
product of roots p*q*1*-1=12, pq= -12 substituting p = -12/q
-12/q+q = 1, multiplying q on both sides
q²-12=q, q²-q-12=0, q²-4q+3q-12 = 0, q(q-4q)+3(q-4)=0
(q-4)(q+3) = 0 hence the roots are 4,-3 also
Hence 1,-1,4, and -3 are the roots of the equation.
Learn more about the Biquadratic equation here
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