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Bob says that he can find the area of the triangle below using the formula: A = [tex]\frac{1}{2}[/tex] * 8 *18 * sin (120°). Is he correct? Explain why or why not.

Bob says that he can find the area of the triangle below using the formula A texfrac12tex 8 18 sin 120 Is he correct Explain why or why not class=

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xKelvin

Answer:

No.

Step-by-step explanation:

No, Bob is not correct.

The formula he's using is the following:

[tex]A=\frac{1}{2} ab\sin(C)[/tex]

The important thing here is that the angle is between the two sides.

In the given triangle, 120 is not between 8 and 18. Therefore, using this formula will not be valid.

Either Bob needs to find the other side first or find the angle between 8 and 18.

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