The polynomial function f (x) = 5 x Superscript 5 Baseline + sixteen-fifths x minus 3 is graphed below. On a coordinate plane, point P is shown on the graph of a function. Point P is at (0.6, 0). Which is a potential rational root of f(x) at point P?

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Answer:

3/5

Step-by-step explanation:

What divisor is represented by the synthetic division below? x + 5. One factor of  x^3+x^2+x+1. If f(-5) = 0, what are all the factors of the function mc022-... -4 and 3. The polynomial function f(x) = 5x5 + 3x - 3 is graphed below. The root at point P maybe 3/5  3.

The potential rational roots are: [tex]\pm 1, \pm \frac{1}{5}, \pm 3,\pm \frac{3}{5}[/tex]

What is the rational root theorem?

The rational root theorem is used to determine the possible rational roots of a polynomial function

The equation of the function is given as:

[tex]f(x) = 5x^5 +\frac{16}{5} x -3[/tex]

Considering a polynomial function, f(x).

Such that:

[tex]f(x) = px^n + .......... +q[/tex]

The possible rational roots are:

[tex]Roots =\pm \frac{Factors\ of\ q}{Factors\ of\ p}[/tex]

So, we have:

[tex]Roots =\pm \frac{Factors\ of\ 3}{Factors\ of\ 5}[/tex]

List the factors of 3 and 5

[tex]Roots =\pm \frac{1,3}{1,5}[/tex]

Split

[tex]Roots =\pm \frac{1}{1}, \pm \frac{1}{5}, \pm \frac{3}{1},\pm \frac{3}{5}[/tex]

Simplify

[tex]Roots =\pm 1, \pm \frac{1}{5}, \pm 3,\pm \frac{3}{5}[/tex]

Hence, the potential rational roots are:

[tex]\pm 1, \pm \frac{1}{5}, \pm 3,\pm \frac{3}{5}[/tex]

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