Answer:
[tex]\large \boxed{\sf \bold{A.} \ x=11.21}[/tex]
Step-by-step explanation:
[tex]\large \sf log_3 (x)=2.2[/tex]
Solve this by converting the logarithmic statement into its equivalent exponential form, using the relationship:
[tex]\large \sf log_b(y)=x[/tex]
[tex]\large{\sf y=b^x}[/tex]
Apply the relationship.
[tex]\large \sf log_3 (x)=2.2[/tex]
[tex]\large \sf x=3^{2.2}[/tex]
[tex]\large \sf x=11.21157845...[/tex]
[tex]\large \sf x \approx 11.21[/tex]
