Answer:
s = 40.2 m
Step-by-step explanation:
It is given that,
Initial speed of the car, u = 0 m/s
Final speed of the car, v = 13.6 m/s
Acceleration of the car, a = 2.3 m/s²
We need to find the distance, s, that it has travelled since stopping at the lights. For this, we will use third equation of motion as :
[tex]v^2-u^2=2as[/tex]
s is distance
[tex]s=\dfrac{v^2-u^2}{2a}\\\\s=\dfrac{(13.6)^2-0}{2\times 2.3}\\\\s=40.2\ m[/tex]
So, the distance covered by the car is 40.2 meters.