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A box of colored crayons contains 11 distinct colors. In how many ways can 2 colors be chosen, assuming that the order of the colors chosen doesn’t matter? (If necessary consult a list of formulas.)

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wegnerkolmp2741o

Answer:

55

Step-by-step explanation:

The first crayon is chosen out of 11,so there are 11 choices

11

The second crayon is chosen out of 10 crayons left so there are 10 choices

10

11*10 = 110

But we do not care about the order, so we divide by 2 since there are 2 places

110/2 =55

MagnusMentula

Answer:

55

Step-by-step explanation:

Equation is a = n * (n-1)

11 * 10 = 110

Order doesn't matter, and two colors, so divide by 2.

110/2 = 55

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